49x^2-49x+6=0

Solution for 49x^2-49x+6=0 equation:

49x^2-49x+6=0

a = 49; b = -49; c = +6;
Δ = b2-4ac
Δ = -492-4·49·6
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-35}{2*49}=\frac{14}{98}
=1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+35}{2*49}=\frac{84}{98}
=6/7
$